Steven Adams vs. Joe Holup Season by Season Comparison

Side by side comparison of each NBA season of Joe Holup and Steven Adams, from their rookie seasons to their last year played, in chronological order with awards, stats, championships and playoff performance of their teams every year.

Who had the better rookie season? Who had best stats in their 10th season? Who won a championship first? These questions and many others, are answered here.

Steven Adams played 10 years in the NBA, 7 more than Joe Holup, who played 3. Steven Adams had the first of his seasons in 2013-14, while Joe Holup had his rookie season in 1956-57. With that starting point, here you can take a look at each of their seasons side by side and compare how their careers evolved in achivements, awards and championships won, the stats they recorded both in the Regular Season and the Playoffs and how their teams performed in the postseason.

Comparison Season by Season
Jump to season: 1-2-3-4-5-6-7-8-9-10
Rookie Season
	Steven Adams	Joe Holup
Season	2013-14	1956-57
Team	Oklahoma City Thunder	Syracuse Nationals
Honors & Awards	All-Rookie Second Team	-
Playoffs	Thunder Lost West Conf Finals	Nationals Lost East Div Finals

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Regular Season Stats
	G	Min	Pts	ORb	DRb	Reb	Ast	Stl	Blk	TO	PF	FGM / A		%	3PM / A		%	FTM / A		%
Steven Adams	81	14.8	3.3	1.8	2.3	4.1	0.5	0.5	0.7	0.9	2.5	1.1	2.3	.503	0.0	0.0	-	1.0	1.7	.581
Joe Holup	71	18.1	7.4	-	-	3.9	1.2	-	-	-	2.5	2.3	6.9	.329	-	-	-	2.9	3.6	.806
Playoffs Stats
	G	Min	Pts	ORb	DRb	Reb	Ast	Stl	Blk	TO	PF	FGM / A		%	3PM / A		%	FTM / A		%
Steven Adams	18	18.4	3.9	1.2	2.9	4.1	0.2	0.1	1.3	0.6	2.7	1.7	2.5	.689	0.0	0.0	-	0.4	1.3	.348
Joe Holup	5	17.6	4.0	-	-	4.0	0.2	-	-	-	0.6	1.2	5.6	.214	-	-	-	1.6	2.4	.667