Ty Lawson vs. Collin Sexton Season by Season Comparison

Side by side comparison of each NBA season of Collin Sexton and Ty Lawson, from their rookie seasons to their last year played, in chronological order with awards, stats, championships and playoff performance of their teams every year.

Who had the better rookie season? Who had best stats in their 10th season? Who won a championship first? These questions and many others, are answered here.

Ty Lawson played 9 years in the NBA, 3 more than Collin Sexton, who played 6. Ty Lawson had the first of his seasons in 2009-10, while Collin Sexton had his rookie season in 2018-19. With that starting point, here you can take a look at each of their seasons side by side and compare how their careers evolved in achivements, awards and championships won, the stats they recorded both in the Regular Season and the Playoffs and how their teams performed in the postseason.

Comparison Season by Season
Jump to season: 1-2-3-4-5-6-7-8-9
Rookie Season
	Ty Lawson	Collin Sexton
Season	2009-10	2018-19
Team	Denver Nuggets	Cleveland Cavaliers
Honors & Awards	-	All-Rookie Second Team
Playoffs	Nuggets Lost West Conf 1st Rd	Did Not Play

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Regular Season Stats
	G	Min	Pts	ORb	DRb	Reb	Ast	Stl	Blk	TO	PF	FGM / A		%	3PM / A		%	FTM / A		%
Ty Lawson	65	20.3	8.3	0.6	1.3	1.9	3.1	0.7	0.0	1.3	1.4	3.1	6.0	.515	0.5	1.3	.410	1.6	2.2	.757
Collin Sexton	82	31.8	16.7	0.7	2.2	2.9	3.0	0.5	0.1	2.3	2.3	6.3	14.7	.430	1.5	3.6	.402	2.6	3.1	.839
Playoffs Stats
	G	Min	Pts	ORb	DRb	Reb	Ast	Stl	Blk	TO	PF	FGM / A		%	3PM / A		%	FTM / A		%
Ty Lawson	6	19.7	7.8	0.7	0.7	1.3	2.7	1.0	0.0	1.3	3.0	2.5	5.8	.429	0.7	1.7	.400	2.2	3.2	.684
Collin Sexton	-	-	-	-	-	-	-	-	-	-	-	-	-	-	-	-	-	-	-	-